Tuesday 21 February 2017
mysql - mysql_connect in php 5.6 +
Answer
Answer
I was using PHP 5.4 in Godaddy Hosting. I have one PHP script which was working fine in it. Now I have changed Hosting and New Hosting company Provide PHP 5.6. I do not PHP coding. I am getting error in my script as below
Deprecated: mysql_connect(): The mysql extension is deprecated and will be removed in the future: use mysqli or PDO instead in /home4/z4g9f1v6/public_html/mydomain.com/folder/config.php on line 7
My Configure file is like below
$mysql_hostname = "localhost";
$mysql_user = "dbuser";
$mysql_password = "dbpass";
$mysql_database = "dbname";
$bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Could not connect database");
mysql_select_db($mysql_database, $bd) or die("Could not select database");
and I am using it in my Search.php like below
include("config.php");
if($_SERVER["REQUEST_METHOD"] == "POST")
{
mysql_query('SET character_set_results=utf8');
mysql_query('SET names=utf8');
mysql_query('SET character_set_client=utf8');
mysql_query('SET character_set_connection=utf8');
mysql_query('SET character_set_results=utf8');
mysql_query('SET collation_connection=utf8_general_ci');
$q=$_POST['q'];
$q=mysql_escape_string($q);
$q_fix=str_replace(" ","%",$q); // Space replacing with %
$sql=mysql_query("SELECT qu_text FROM quotes WHERE qu_text LIKE '%$q%'");
}while($row=mysql_fetch_array($sql)){$title=$row['qu_text'];
Please help me. How can I solve the issue ?
Thanks
Answer
For Myqli connection
$mysql_hostname = "localhost";
$mysql_user = "dbuser";
$mysql_password = "dbpass";
$mysql_database = "dbname";
$bd = mysqli_connect($mysql_hostname, $mysql_user, $mysql_password,$mysql_database) or die("Could not connect database");
For Query Please follow this answer How can I prevent SQL injection in PHP? it's really nice.
You could use this for query
$sql=sprintf("SELECT qu_text FROM `quotes` WHERE qu_text LIKE '%s%%'"),mysqli_real_escape_string($bd,$q));
$fetch= mysqli_query($bd,$sql) or die(mysql_error());
while ($row = mysqli_fetch_array($fetch, MYSQLI_ASSOC)) {
//Your Result
}
Most of mysql_ syntax you could use with mysqli_
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