Tuesday, 28 February 2017

If statement structure in PHP




I keep getting an error with the following bit of code. It is probably some small thing but I don't see what is wrong.




while($row = mysql_fetch_array($result))
{
$varp = $row['ustk_retail'];
if ($varp<80000) { $o1 = 1; }
if (($varp=>80000) && ($varp<100000)) { $o2 = "1"; }
if (($varp=>100000) && ($varp<120000)) { $o3 = "1"; }
if (($varp=>120000) && ($varp<140000)) { $o4 = "1"; }

if (($varp=>140000) && ($varp<160000)) { $o5 = "1"; }
if (($varp=>160000) && ($varp<180000)) { $o6 = "1"; }
if (($varp=>180000) && ($varp<200000)) { $o7 = "1"; }
if (($varp=>200000) && ($varp<220000)) { $o8 = "1"; }
if (($varp=>220000) && ($varp<240000)) { $o9 = "1"; }
if (($varp=>240000) && ($varp<260000)) { $o10 = "1"; }
if (($varp=>260000) && ($varp<280000)) { $o11 = "1"; }
if (($varp=>280000) && ($varp<300000)) { $o12 = "1"; }
if ($varp>=300000) { $o13 = "1"; }
}


Answer



Greater than or equal to is >= sign, not =>



Update:
You are right. It's small but hard to find mistake.
It took me to split whole line into pieces to see where the problem is:



if 
(
$varp

=>
80000
)


So, it says parse error on line 5 and I had to doublecheck this operator.
Of course, at first I separated the problem line from the rest of the code to be certain.


No comments:

Post a Comment

c++ - Does curly brackets matter for empty constructor?

Those brackets declare an empty, inline constructor. In that case, with them, the constructor does exist, it merely does nothing more than t...