Tuesday 25 April 2017

linux - Looping through the content of a file in Bash



How do I iterate through each line of a text file with Bash?




With this script:



echo "Start!"
for p in (peptides.txt)
do
echo "${p}"
done


I get this output on the screen:




Start!
./runPep.sh: line 3: syntax error near unexpected token `('
./runPep.sh: line 3: `for p in (peptides.txt)'


(Later I want to do something more complicated with $p than just output to the screen.)







The environment variable SHELL is (from env):



SHELL=/bin/bash


/bin/bash --version output:



GNU bash, version 3.1.17(1)-release (x86_64-suse-linux-gnu)
Copyright (C) 2005 Free Software Foundation, Inc.



cat /proc/version output:



Linux version 2.6.18.2-34-default (geeko@buildhost) (gcc version 4.1.2 20061115 (prerelease) (SUSE Linux)) #1 SMP Mon Nov 27 11:46:27 UTC 2006


The file peptides.txt contains:



RKEKNVQ
IPKKLLQK

QYFHQLEKMNVK
IPKKLLQK
GDLSTALEVAIDCYEK
QYFHQLEKMNVKIPENIYR
RKEKNVQ
VLAKHGKLQDAIN
ILGFMK
LEDVALQILL

Answer




One way to do it is:



while read p; do
echo "$p"
done


As pointed out in the comments, this has the side effects of trimming leading whitespace, interpreting backslash sequences, and skipping the last line if it's missing a terminating linefeed. If these are concerns, you can do:



while IFS="" read -r p || [ -n "$p" ]

do
printf '%s\n' "$p"
done < peptides.txt





Exceptionally, if the loop body may read from standard input, you can open the file using a different file descriptor:



while read -u 10 p; do

...
done 10


Here, 10 is just an arbitrary number (different from 0, 1, 2).


No comments:

Post a Comment

c++ - Does curly brackets matter for empty constructor?

Those brackets declare an empty, inline constructor. In that case, with them, the constructor does exist, it merely does nothing more than t...