Wednesday 25 May 2016

java - Both next() and nextLine() not helping to store name with spacing



I am currently using a Scanner to record the user input which is a String and print it out. If the user input is a single name such as Alan, it works fine. If I enter a name with spacing such as Alan Smith, it returns an error saying InputMisMatchException.



I read around similar cases here and they advised to use nextLine() instead of next(). It made sense but that doesn't work for me either. When I use a nextLine(), it immediately skips the step where I enter the name and goes back to the starting of the loop asking me to input choice again. Please advice how I can correct this. Thank you.



import java.io.IOException;
import java.util.Scanner;

public class ScannerTest {
static String name;
static Scanner in = new Scanner(System.in);
static int choice;

public static void main(String[] args) {
while(choice != 5){
System.out.print("\nEnter Choice :> ");
choice = in.nextInt();

if(choice == 1){
try{
printName();
}
catch(IOException e){
System.out.println("IO Exception");
}
}
}
}
private static void printName()throws IOException{
System.out.print("\nEnter name :> ");
name = in.next();
//name = in.nextLine();
if (name != null){
System.out.println(name);
}
}
}

Answer



Try this instead: add name = in.nextLine(); after choice = in.nextInt();.



Then try replacing name = in.next(); with name = in.nextLine();



Explanation: After the scanner calls nextInt() it gets the first value and leaves the rest of the string to the \n. We then consume the rest of the string with nextLine().



The second nextLine() is then used to get your string parameters.


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