Thursday, 26 May 2016

c - Why does GCC use multiplication by a strange number in implementing integer division?

I've been reading about div and mul assembly operations, and I decided to see them in action by writing a simple program in C:




File division.c



#include 
#include

int main()
{
size_t i = 9;
size_t j = i / 5;

printf("%zu\n",j);
return 0;
}


And then generating assembly language code with:



gcc -S division.c -O0 -masm=intel



But looking at generated division.s file, it doesn't contain any div operations! Instead, it does some kind of black magic with bit shifting and magic numbers. Here's a code snippet that computes i/5:



mov     rax, QWORD PTR [rbp-16]   ; Move i (=9) to RAX
movabs rdx, -3689348814741910323 ; Move some magic number to RDX (?)
mul rdx ; Multiply 9 by magic number
mov rax, rdx ; Take only the upper 64 bits of the result
shr rax, 2 ; Shift these bits 2 places to the right (?)
mov QWORD PTR [rbp-8], rax ; Magically, RAX contains 9/5=1 now,
; so we can assign it to j



What's going on here? Why doesn't GCC use div at all? How does it generate this magic number and why does everything work?

No comments:

Post a Comment

c++ - Does curly brackets matter for empty constructor?

Those brackets declare an empty, inline constructor. In that case, with them, the constructor does exist, it merely does nothing more than t...