Always confused about this stuff. Anyone can help?
Answer
string1.equals(string2) is the way.
string1.equals(string2)
It returns true if string1 is equals to string2 in value. Else, it will return false.
true
string1
string2
false
equals reference
Those brackets declare an empty, inline constructor. In that case, with them, the constructor does exist, it merely does nothing more than t...
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