I cannot understand why a call to read after an lseek returns 0 number of bytes read.
//A function to find the next note for a given userID;
//returns -1 if at the end of file is reached;
//otherwise, it returns the length of the found note.
int find_user_note(int fd, int user_uid) {
int note_uid = -1;
unsigned char byte;
int length;
while(note_uid != user_uid) { // Loop until a note for user_uid is found.
if(read(fd, ¬e_uid, 4) != 4) // Read the uid data.
return -1; // If 4 bytes aren't read, return end of file code.
if(read(fd, &byte, 1) != 1) // Read the newline separator.
return -1;
byte = length = 0;
while(byte != '\n') { // Figure out how many bytes to the end of line.
if(read(fd, &byte, 1) != 1) // Read a single byte.
return -1; // If byte isn't read, return end of file code.
//printf("%x ", byte);
length++;
}
}
long cur_position = lseek(fd, length * -1, SEEK_CUR ); // Rewind file reading by length bytes.
printf("cur_position: %i\n", cur_position);
// this is debug
byte = 0;
int num_byte = read(fd, &byte, 1);
printf("[DEBUG] found a %d byte note for user id %d\n", length, note_uid);
return length;
}
The variable length value is 34 when it exist the outer while loop and the above code produces cur_position 5 (so there are definitely at least 34 bytes after the lseek function returns), but the variable num_byte returned from function read always returns 0 even though there are still more bytes to read.
Does anyone know the reason num_byte always return 0? If it is a mistake in my code, am not seeing what it is.
Just for information, the above code was run on the following machine
$ uname -srvpio
Linux 3.2.0-24-generic #39-Ubuntu SMP Mon May 21 16:52:17 UTC 2012 x86_64 x86_64 GNU/Linux
Update:
- I upload the full code here
- This is the content of file that I try to read
$ sudo hexdump -C /var/notes
00000000 e8 03 00 00 0a 74 68 69 73 20 69 73 20 61 20 74 |.....this is a t|
00000010 65 73 74 20 6f 66 20 6d 75 6c 74 69 75 73 65 72 |est of multiuser|
00000020 20 6e 6f 74 65 73 0a | notes.|
00000027
$
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