a = [1, 2, 3, 4]
b = a.index(6)
del a[b]
print a
The above shows the following error:
Traceback (most recent call last):
File "D:\zjm_code\a.py", line 6, in
b = a.index(6)
ValueError: list.index(x): x not in list
So I have to do this:
a = [1, 2, 3, 4]
try:
b = a.index(6)
del a[b]
except:
pass
print a
But is there not a simpler way to do this?
Answer
To remove an element's first occurrence in a list, simply use list.remove
:
>>> a = ['a', 'b', 'c', 'd']
>>> a.remove('b')
>>> print a
['a', 'c', 'd']
Mind that it does not remove all occurrences of your element. Use a list comprehension for that.
>>> a = [10, 20, 30, 40, 20, 30, 40, 20, 70, 20]
>>> a = [x for x in a if x != 20]
>>> print a
[10, 30, 40, 30, 40, 70]
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