javascript - What is the best way to add options to a select from as a JS object with jQuery?

What is the best method for adding options to a from a JavaScript object using jQuery?I'm looking for something that I don't need a plugin to do, but I would also be interested in the plugins that are out there.This is what I did:selectValues = { "1": "test 1", "2": "test 2" };for (key in selectValues) { if (typeof (selectValues[key] == 'string') { $('#mySelect').append('' + selectValues[key] + ''); }}A clean/simple solution:This is a cleaned up and simplified version of matdumsa's:$.each(selectValues, function(key, value) { $('#mySelect') .append($('', { value : key }) .text(value));});Changes from matdumsa's: (1) removed the close tag for the option inside append() and (2) moved the properties/attributes into an map as the second parameter of append(). Answer Same as other answers, in jQuery fashion:$.each(selectValues, function(key, value) { $('#mySelect') .append($("") .attr("value",key) .text(value)); }); - January 23, 2016 Email ThisBlogThis!Share to XShare to FacebookShare to Pinterest No comments: Post a Comment Newer Post Older Post Home Subscribe to: Post Comments (Atom) c++ - Does curly brackets matter for empty constructor? Those brackets declare an empty, inline constructor. In that case, with them, the constructor does exist, it merely does nothing more than t... .image { width: 100%; } analysis - Were parts of The Dark Knight Rises a commentary on the Occupy movement? - Movies & TV A fair amount of the second act of The Dark Knight Rises has a class warfare plotline. This is foreshadowed in the trailers with Selina Ky... javascript - Create multidimensional array from string I want to create an options array from a string. How can i create an array as { width : 100, height : 200 } from a string ... c# - How to fix "The body of 'display(List)' cannot be an iterator block because 'string' is not an iterator interface type"? I'm new to Programming. I would like to implement a program with a yield keyword . So That, I have created a new List and ask the user ... Search This Blog