I have two JavaScript arrays:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
I want the output to be:
var array3 = ["Vijendra","Singh","Shakya"];
The output array should have repeated words removed.
How do I merge two arrays in JavaScript so that I get only the unique items from each array in the same order they were inserted into the original arrays?
Answer
To just merge the arrays (without removing duplicates)
ES5 version use Array.concat
:
var array1 = ["Vijendra", "Singh"];
var array2 = ["Singh", "Shakya"];
console.log(array1.concat(array2));
ES6 version use destructuring
const array1 = ["Vijendra","Singh"];
const array2 = ["Singh", "Shakya"];
const array3 = [...array1, ...array2];
Since there is no 'built in' way to remove duplicates (ECMA-262 actually has Array.forEach
which would be great for this), we have to do it manually:
Array.prototype.unique = function() {
var a = this.concat();
for(var i=0; i for(var j=i+1; j if(a[i] === a[j])
a.splice(j--, 1);
}
}
return a;
};
Then, to use it:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
// Merges both arrays and gets unique items
var array3 = array1.concat(array2).unique();
This will also preserve the order of the arrays (i.e, no sorting needed).
Since many people are annoyed about prototype augmentation of Array.prototype
and for in
loops, here is a less invasive way to use it:
function arrayUnique(array) {
var a = array.concat();
for(var i=0; i for(var j=i+1; j if(a[i] === a[j])
a.splice(j--, 1);
}
}
return a;
}
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
// Merges both arrays and gets unique items
var array3 = arrayUnique(array1.concat(array2));
For those who are fortunate enough to work with browsers where ES5 is available, you can use Object.defineProperty
like this:
Object.defineProperty(Array.prototype, 'unique', {
enumerable: false,
configurable: false,
writable: false,
value: function() {
var a = this.concat();
for(var i=0; i for(var j=i+1; j if(a[i] === a[j])
a.splice(j--, 1);
}
}
return a;
}
});
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